import math
import time
def lenta (n):
    '''

    :param n:
    :return:
    '''
    soma = 0.0
    for k in range (n):
        for j in range (n):
            soma += math.sqrt (n)
t1 = time.clock()
a = lenta (10000)
t2 = time.clock()
print t2-t1